AM-1013

Trigonometric equations

A Math · Secondary 3 · Hard · Trigonometric equations

Solve the equation

2\sin\theta\cos\theta=\cos\theta

for

-\pi<\theta<\pi

.

$\theta=-\dfrac{\pi}{2},\dfrac{\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}$
$\theta=-\dfrac{\pi}{2},\dfrac{\pi}{2},-\dfrac{\pi}{6},\dfrac{\pi}{6}$
$\theta=-\dfrac{\pi}{2},\dfrac{\pi}{2},\dfrac{\pi}{6}$
$\theta=-\dfrac{\pi}{2},0,\dfrac{\pi}{2}$

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