A box has volume (3x−1)2 cm3. Its rectangular base has dimensions x cm by (x+2) cm. Find an expression for the height of the box in cm, simplifying your answer into partial fractions.
9−2x35+2(x+2)23
9+2x1−2(x+2)49
9−2x23+2(x+2)35
9+2x23+2(x+2)35
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