AM-1700

Differentiating standard functions

A Math · Secondary 4 · Medium · Differentiating standard functions

The total surface area

S

of a solid (in

\text{cm}^2

) is given by

S = 50\left(\dfrac{1}{x} + \dfrac{x^2}{25}\right)

, where

x>0

. Find

\dfrac{dS}{dx}

.

$\dfrac{dS}{dx} = -\dfrac{50}{x^2} + 4x$
$\dfrac{dS}{dx} = \dfrac{50}{x^2} + 4x$
$\dfrac{dS}{dx} = -\dfrac{50}{x} + 4x^2$
$\dfrac{dS}{dx} = -\dfrac{1}{50x^2} + \dfrac{2x}{25}$

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