AM-1881

Product rule

A Math · Secondary 4 · Medium · Product rule

The area of a rectangle inside a semicircle is given by

A=\dfrac{x}{2}\sqrt{196-x^2}

, where

x

is in cm. Find

\dfrac{dA}{dx}

.

$\dfrac{1}{2}\sqrt{196-x^2}-\dfrac{x^2}{2\sqrt{196-x^2}}$
$\dfrac{1}{2}\sqrt{196-x^2}+\dfrac{x^2}{2\sqrt{196-x^2}}$
$\sqrt{196-x^2}-\dfrac{x^2}{\sqrt{196-x^2}}$
$\dfrac{1}{2}\sqrt{196-x^2}$

Sign in to check your answer and see the hint and the worked explanation. Free on PrepLab High.

Loading problem…