AM-1954

Stationary points

A Math · Secondary 4 · Hard · Stationary points

The gradient of the tangent to a curve at any point is given by

\frac{dy}{dx} = 4x - 1

. Find the coordinates of the stationary point of the curve.

$\left(\dfrac{1}{4}, -\dfrac{1}{8}\right)$
$\left(\dfrac{1}{4}, \dfrac{1}{8}\right)$
$\left(-\dfrac{1}{4}, -\dfrac{1}{8}\right)$
$\left(-\dfrac{1}{4}, \dfrac{1}{8}\right)$

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