AM-2150

Integrating standard functions

A Math · Secondary 4 · Hard · Integrating standard functions

Given

\dfrac{dy}{dx} = 6x^2 - 4x + 1

and

y = 0

when

x = 1

, find

y

in terms of

x

.

$y = 2x^3 - 2x^2 + x - 1$
$y = 2x^3 - 2x^2 + x + 1$
$y = 2x^3 - 4x^2 + x - 1$
$y = 6x^3 - 4x^2 + x - 1$

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