AM-2224

Quotient rule

A Math · Secondary 4 · Medium · Quotient rule

Given

y = \dfrac{5x-3}{x+4}

, find

\dfrac{dy}{dx}

.

$\dfrac{23}{(x+4)^2}$
$\dfrac{5}{x+4}$
$\dfrac{5x-3}{(x+4)^2}$
$\dfrac{23}{x+4}$

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