AM-2272

Product rule

A Math · Secondary 4 · Medium · Product rule

Differentiate

y=x(4x-1)^{\frac{5}{3}}

with respect to

x

.

$y'=(4x-1)^{\frac{5}{3}}+\tfrac{20}{3}x(4x-1)^{\frac{2}{3}}$
$y'=(4x-1)^{\frac{5}{3}}+\tfrac{5}{3}x(4x-1)^{\frac{2}{3}}$
$y'=x\tfrac{20}{3}(4x-1)^{\frac{5}{3}}$
$y'=(4x-1)^{\frac{2}{3}}$

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