AM-2577

Principal values

A Math · Secondary 4 · Easy · Principal values

The principal value of

\sin^{-1}x

lies between two fixed angles. Which of the following gives the correct range in radians?

$-\dfrac{\pi}{2} \le \sin^{-1}x \le \dfrac{\pi}{2}$
$0 \le \sin^{-1}x \le \pi$
$-\pi \le \sin^{-1}x \le 0$
$0 \le \sin^{-1}x \le \dfrac{\pi}{2}$

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