AM-2592

Principal values

A Math · Secondary 4 · Hard · Principal values

Solve the equation

\csc x + \cot x = 2

for

0\le x\le 2\pi

.

$x = 2\tan^{-1}\dfrac12$
$x = \tan^{-1}\dfrac12$
$x = \pi - 2\tan^{-1}\dfrac12$
$x = 2\pi - 2\tan^{-1}\dfrac12$

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