AM-2620

Trigonometric equations

A Math · Secondary 4 · Hard · Trigonometric equations

Solve

\tan 2x = \sqrt{3}

for

0 \le x \le \pi

.

$x = \dfrac{\pi}{6},\dfrac{2\pi}{3}$
$x = \dfrac{\pi}{3},\dfrac{2\pi}{3}$
$x = \dfrac{\pi}{6},\dfrac{5\pi}{6}$
$x = \dfrac{\pi}{6},\dfrac{\pi}{2},\dfrac{5\pi}{6}$

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