AM-2664

Trigonometric equations

A Math · Secondary 4 · Hard · Trigonometric equations

Solve the trigonometric equation

2\sin^2 x - 3\sin x + 1 = 0

for

0^\circ \le x \le 360^\circ

.

$x = 30^\circ, 90^\circ, 150^\circ$
$x = 30^\circ, 150^\circ, 210^\circ$
$x = 30^\circ, 210^\circ, 330^\circ$
$x = 90^\circ, 270^\circ$

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