AM-432

Quadratic inequalities

A Math · Secondary 3 · Medium · Quadratic inequalities

A curve has equation

y = x^2 - 4x + 1

. Find the range of values of

x

for which

y \le 0

.

$2-\sqrt{3}\le x\le2+\sqrt{3}$
$x\le2-\sqrt{3}\text{ or }x\ge2+\sqrt{3}$
$x\ge2-\sqrt{3}$
$x\le2+\sqrt{3}$

Sign in to check your answer and see the hint and the worked explanation. Free on PrepLab High.

Loading problem…