AM-521

Exponential and logarithmic equations

A Math · Secondary 3 · Hard · Exponential and logarithmic equations

Solve for

x

:

3^{2x}-3=4\cdot3^x

.

$x=\log_3(2+\sqrt7)$ or $x=\log_3(2-\sqrt7)$
$x=2\pm\sqrt7$
$x=\log_3(4\pm\sqrt7)$
$x=\log_3(2+\sqrt7)$

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