AM-676

Tangents and normals

A Math · Secondary 3 · Medium · Tangents and normals

Given

f(x)=\dfrac{5x-3}{x+2}

, find the equation of the tangent to the curve at the point where

x=1

.

$y=\dfrac{13}{9}x-\dfrac{4}{9}$
$y=\dfrac{13}{9}x+1$
$y=\dfrac{9}{13}x-\dfrac{4}{9}$
$y=\dfrac{13}{9}x+\dfrac{4}{9}$

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