AM-908

Principal values

A Math · Secondary 3 · Easy · Principal values

Find the principal value of

\sin^{-1}\!\left(\dfrac{\sqrt{3}}{2}\right)

in radians.

$\dfrac{\pi}{3}$
$\dfrac{2\pi}{3}$
$\dfrac{\pi}{6}$
$\dfrac{5\pi}{6}$

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