CH-2050
The mole
Chemistry · Secondary 4 · Hard · The mole
A refinery can use either calcium carbonate or magnesium carbonate to remove 640 kg of SO per hour.
Data:
- Reaction mole ratio with SO is 1:1 for both carbonates.
- Molar masses: CaCO = 100 g/mol, MgCO = 84 g/mol, SO = 64 g/mol.
- Costs: CaCO = \$0.12/kg, MgCO = \$0.16/kg.
Which reagent is cheaper per hour?
Data:
- Reaction mole ratio with SO is 1:1 for both carbonates.
- Molar masses: CaCO = 100 g/mol, MgCO = 84 g/mol, SO = 64 g/mol.
- Costs: CaCO = \$0.12/kg, MgCO = \$0.16/kg.
Which reagent is cheaper per hour?
- Calcium carbonate, costing \20
- Magnesium carbonate, costing \07.52
- Calcium carbonate, costing \$64
- Magnesium carbonate, costing \60
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