EM-1372

Pythagoras’ theorem

E Math · Secondary 3 · Hard · Pythagoras’ theorem

In

\triangle PQR

,

PQ = 7\text{ cm}

,

PR = 25\text{ cm}

and

QR = 24\text{ cm}

. Show that

\angle P

is a right angle by using the converse of Pythagoras’ theorem.

Which statement is correct?

$PQ^2 + QR^2 = PR^2$ , so $\angle P$ is a right angle.
$PQ^2 + PR^2 = QR^2$ , so $\angle P$ is a right angle.
$QR^2 + PR^2 = PQ^2$ , so $\angle P$ is a right angle.
$PQ^2 + QR^2 = PR^2$ , so $\angle R$ is a right angle.

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