EM-1564

Changing the subject of a formula

E Math · Secondary 4 · Hard · Changing the subject of a formula

Given that

p = \dfrac{4h-3}{2h+1}

, express

h

in terms of

p

.

$h = \dfrac{p+3}{4-2p}$
$h = \dfrac{p-3}{4-2p}$
$h = \dfrac{p+3}{2p-4}$
$h = \dfrac{4p-3}{2p+1}$

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