EM-1664

Changing the subject of a formula

E Math · Secondary 4 · Hard · Changing the subject of a formula

It is given that

\dfrac{3p-1}{q} = \dfrac{2}{p}

.

Express

p

in terms of

q

.

$p = \dfrac{1 + \sqrt{1+24q}}{6}$ or $p = \dfrac{1 - \sqrt{1+24q}}{6}$
$p = \dfrac{1 + \sqrt{1-24q}}{6}$ or $p = \dfrac{1 - \sqrt{1-24q}}{6}$
$p = \dfrac{-1 \pm \sqrt{1+24q}}{6}$
$p = \dfrac{1 \pm \sqrt{24q-1}}{6}$

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