EM-2008

Graphs of power functions

E Math · Secondary 4 · Hard · Graphs of power functions

1. Because $x=0$ on the $y$-axis makes $\dfrac{1}{x^3}+\dfrac{1}{2x}$ undefined, so the curve cannot exist there.
2. Because $y$ is always zero when $x=0$, so the curve is a horizontal line.
3. Because the curve only exists for positive values of $x$.
4. Because the gradient of the curve is zero on the $y$-axis.

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