EM-2325

Laws of indices

E Math · Secondary 4 · Easy · Laws of indices

Simplify

\dfrac{4x^{-2}y^3}{8x y^{-1}}

and leave your answer in positive index notation.

$\dfrac{y^4}{2x^3}$
$\dfrac{2y^4}{x^3}$
$\dfrac{y^2}{2x}$
$\dfrac{x^3}{2y^4}$

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