EM-2712

Inverse proportion

E Math · Secondary 4 · Hard · Inverse proportion

It is given that

y^3

is inversely proportional to the square of

x

. The difference between the values of

y^3

when

x=2

and when

x=4

is 6. Find the values of

x

when

y=3

.

$x = \pm \dfrac{4\sqrt{6}}{9}$
$x = \pm \dfrac{9}{4\sqrt{6}}$
$x = \pm \dfrac{4\sqrt{3}}{9}$
$x = \pm \dfrac{2\sqrt{6}}{3}$

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