EM-3135

Position vectors

E Math · Secondary 4 · Hard · Position vectors

Point

P

has coordinates

(2,5)

. The vector

\overrightarrow{PQ} = \begin{pmatrix}6\\-4\end{pmatrix}

. Find the equation of the line

PQ

in the form

y = mx + c

.

$y = -\dfrac{2}{3}x + \dfrac{19}{3}$
$y = \dfrac{2}{3}x + \dfrac{7}{3}$
$y = -\dfrac{3}{2}x + \dfrac{19}{3}$
$y = \dfrac{2}{3}x - \dfrac{19}{3}$

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