EM-3161

Vector geometry

E Math · Secondary 4 · Hard · Vector geometry

In a triangle

ABC

,

D

lies on

BC

such that

2BD = DC

.

Given

\vec{AB} = \mathbf{p}

and

\vec{AC} = \mathbf{q}

, express

\vec{AD}

in terms of

\mathbf{p}

and

\mathbf{q}

.

$\dfrac{2}{3}\mathbf{p} + \dfrac{1}{3}\mathbf{q}$
$\dfrac{1}{3}\mathbf{p} + \dfrac{2}{3}\mathbf{q}$
$\dfrac{1}{2}\mathbf{p} + \dfrac{1}{2}\mathbf{q}$
$\mathbf{q} - \dfrac{1}{3}\mathbf{p}$

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