EM-3162

Vector geometry

E Math · Secondary 4 · Hard · Vector geometry

In a triangle

PQR

,

S

lies on

QR

such that

QS : SR = 3 : 1

.

Given

\vec{PQ} = \mathbf{a}

and

\vec{PR} = \mathbf{b}

, express

\vec{PS}

in terms of

\mathbf{a}

and

\mathbf{b}

.

$\dfrac{1}{4}\mathbf{a} + \dfrac{3}{4}\mathbf{b}$
$\dfrac{3}{4}\mathbf{a} + \dfrac{1}{4}\mathbf{b}$
$\dfrac{3}{4}(\mathbf{a}+\mathbf{b})$
$\mathbf{b} - \dfrac{1}{4}\mathbf{a}$

Sign in to check your answer and see the hint and the worked explanation. Free on PrepLab High.

Loading problem…