EM-3163

Vector geometry

E Math · Secondary 4 · Hard · Vector geometry

In triangle

PQR

,

S

lies on

QR

such that

2\,QS = 3\,SR

.

Given

\vec{PQ}=\mathbf{a}

and

\vec{PR}=\mathbf{b}

, express

\vec{PS}

in terms of

\mathbf{a}

and

\mathbf{b}

.

$\dfrac{2}{5}\mathbf{a}+\dfrac{3}{5}\mathbf{b}$
$\dfrac{3}{5}\mathbf{a}+\dfrac{2}{5}\mathbf{b}$
$\dfrac{3}{5}\mathbf{b}-\dfrac{2}{5}\mathbf{a}$
$\dfrac{2}{5}\mathbf{b}-\dfrac{3}{5}\mathbf{a}$

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