EM-3174

Vector geometry

E Math · Secondary 4 · Hard · Vector geometry

In a parallelogram

OABC

,

\overrightarrow{OB} = \mathbf{p}

and

\overrightarrow{OC} = \mathbf{q}

. Point

A

is such that

OABC

is a parallelogram.

Express

\overrightarrow{OA}

in terms of

\mathbf{p}

and

\mathbf{q}

.

$\mathbf{q}$
$\mathbf{p}$
$\mathbf{p} + \mathbf{q}$
$\mathbf{q} - \mathbf{p}$

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