EM-875

Laws of indices

E Math · Secondary 3 · Medium · Laws of indices

Simplify

\dfrac{4a^2b^{-1}}{8a^{-3}b^2}

, leaving your answer with positive indices.

$\dfrac{a^5}{2b^3}$
$\dfrac{2a^5}{b^3}$
$\dfrac{a^{-5}}{2b^3}$
$\dfrac{a^5}{2b^{-3}}$

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