EM-896

Laws of indices

E Math · Secondary 3 · Medium · Laws of indices

Simplify the expression

\left( \dfrac{4a^3}{9b^2} \right)^{-\frac{1}{2}}.

Give your answer with positive indices.

$\dfrac{3b}{2a\sqrt{a}}$
$\dfrac{2a\sqrt{a}}{3b}$
$\dfrac{3\sqrt{b}}{2a^{3/2}}$
$\dfrac{3b^2}{2a^{3/2}}$

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