EM-899

Laws of indices

E Math · Secondary 3 · Medium · Laws of indices

Simplify

\left(\dfrac{4x^3}{9y^6}\right)^{-\frac{1}{2}}.

$\dfrac{3y^3}{2x^{3/2}}$
$\dfrac{2x^{3/2}}{3y^3}$
$\dfrac{3y^3}{2x^3}$
$\dfrac{2x^3}{3y^3}$

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