EM-914

Laws of indices

E Math · Secondary 3 · Medium · Laws of indices

Simplify

\dfrac{4x^2y^{-1}}{2x^{-1}y^3}

, leaving your answer with positive indices only.

$\dfrac{2x^3}{y^4}$
$\dfrac{2x}{y^2}$
$\dfrac{8x^3}{y^2}$
$\dfrac{2x^{-3}}{y^4}$

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