H2P-19

Centripetal force

H2 Physics · JC 1 · Hard · Centripetal force

A 15 g bead is fixed 0.18 m from the centre of a rotating disc. The bead just starts to slip when the disc rotates at 45 revolutions per minute. Using centripetal force, find the maximum frictional force on the bead.

$6.0\times10^{-2}\,\text{N}$
$1.2\times10^{-2}\,\text{N}$
$2.8\times10^{-1}\,\text{N}$
$3.0\times10^{-2}\,\text{N}$

Loading problem…