MA-818

Simultaneous equations by substitution

Lower Sec Maths · Secondary 2 · Hard · Simultaneous equations by substitution

Solve the simultaneous equations using substitution:

y = 3x - 4, \quad 2x + y = 17.

$x = \dfrac{21}{5},\ y = \dfrac{43}{5}$
$x = \dfrac{21}{5},\ y = \dfrac{17}{5}$
$x = \dfrac{43}{5},\ y = \dfrac{21}{5}$
$x = 5,\ y = 11$

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