MA-944

Inverse proportion

Lower Sec Maths · Secondary 2 · Hard · Inverse proportion

It is given that

y

is inversely proportional to

x^2

. When

y = 8

,

x = 3

.

(a) Find the equation connecting

y

and

x

.
(b) Hence find the value of

y

when

x = 6

.

$y = \dfrac{72}{x^2}$ , and $y = 2$ when $x = 6$
$y = \dfrac{24}{x^2}$ , and $y = 1$ when $x = 6$
$y = 8x^2$ , and $y = 288$ when $x = 6$
$y = \dfrac{9}{x^2}$ , and $y = 0.25$ when $x = 6$

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